(a^1/2-31/2)/5^1/2=4b

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Solution for (a^1/2-31/2)/5^1/2=4b equation: 


x in (-oo:+oo)

(((a^1)/2-(31/2))/(5^1))/2 = 4*b // - 4*b

(((a^1)/2-(31/2))/(5^1))/2-(4*b) = 0

((a/2-31/2)/5)/2-4*b = 0

(1/2*a-31/2)/(2*5)-4*b = 0

(1/2*a-31/2)/(2*5)+(-4*2*5*b)/(2*5) = 0

1/2*a-4*2*5*b-31/2 = 0

1/2*a-40*b-31/2 = 0

(1/2*a-40*b-31/2)/(2*5) = 0

(1/2*a-40*b-31/2)/(2*5) = 0 // * 2*5

1/2*a-40*b-31/2 = 0

x belongs to the empty set

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